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Associate-Developer-Apache-Spark-3.5 New Practice Questions | Associate-Developer-Apache-Spark-3.5 Mock Test
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Associate-Developer-Apache-Spark-3.5 New Practice Questions - Realistic Databricks Certified Associate Developer for Apache Spark 3.5 - Python Mock Test
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Databricks Certified Associate Developer for Apache Spark 3.5 - Python Sample Questions (Q64-Q69):
NEW QUESTION # 64
A developer wants to test Spark Connect with an existing Spark application.
What are the two alternative ways the developer can start a local Spark Connect server without changing their existing application code? (Choose 2 answers)
- A. Execute their pyspark shell with the option--remote "https://localhost"
- B. Add.remote("sc://localhost")to their SparkSession.builder calls in their Spark code
- C. Execute their pyspark shell with the option--remote "sc://localhost"
- D. Set the environment variableSPARK_REMOTE="sc://localhost"before starting the pyspark shell
- E. Ensure the Spark propertyspark.connect.grpc.binding.portis set to 15002 in the application code
Answer: C,D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
Spark Connect enables decoupling of the client and Spark driver processes, allowing remote access. Spark supports configuring the remote Spark Connect server in multiple ways:
From Databricks and Spark documentation:
Option B (--remote "sc://localhost") is a valid command-line argument for thepysparkshell to connect using Spark Connect.
Option C (settingSPARK_REMOTEenvironment variable) is also a supported method to configure the remote endpoint.
Option A is incorrect because Spark Connect uses thesc://protocol, nothttps://.
Option D requires modifying the code, which the question explicitly avoids.
Option E configures the port on the server side but doesn't start a client connection.
Final Answers: B and C
NEW QUESTION # 65
A data scientist is working on a large dataset in Apache Spark using PySpark. The data scientist has a DataFrame df with columns user_id, product_id, and purchase_amount and needs to perform some operations on this data efficiently.
Which sequence of operations results in transformations that require a shuffle followed by transformations that do not?
- A. df.filter(df.purchase_amount > 100).groupBy("user_id").sum("purchase_amount")
- B. df.withColumn("discount", df.purchase_amount * 0.1).select("discount")
- C. df.groupBy("user_id").agg(sum("purchase_amount").alias("total_purchase")).repartition(10)
- D. df.withColumn("purchase_date", current_date()).where("total_purchase > 50")
Answer: C
Explanation:
Shuffling occurs in operations like groupBy, reduceByKey, or join-which cause data to be moved across partitions. The repartition() operation can also cause a shuffle, but in this context, it follows an aggregation.
In Option D, the groupBy followed by agg results in a shuffle due to grouping across nodes.
The repartition(10) is a partitioning transformation but does not involve a new shuffle since the data is already grouped.
This sequence - shuffle (groupBy) followed by non-shuffling (repartition) - is correct.
Option A does the opposite: the filter does not cause a shuffle, but groupBy does - this makes it the wrong order.
NEW QUESTION # 66
A data engineer wants to process a streaming DataFrame that receives sensor readings every second with columns sensor_id, temperature, and timestamp. The engineer needs to calculate the average temperature for each sensor over the last 5 minutes while the data is streaming.
Which code implementation achieves the requirement?
Options from the images provided:
- A.
- B.
- C.
- D.
Answer: B
Explanation:
The correct answer is D because it uses proper time-based window aggregation along with watermarking, which is the required pattern in Spark Structured Streaming for time-based aggregations over event-time data.
From the Spark 3.5 documentation on structured streaming:
"You can define sliding windows on event-time columns, and use groupBy along with window() to compute aggregates over those windows. To deal with late data, you use withWatermark() to specify how late data is allowed to arrive." (Source: Structured Streaming Programming Guide) In option D, the use of:
python
CopyEdit
.groupBy("sensor_id", window("timestamp", "5 minutes"))
.agg(avg("temperature").alias("avg_temp"))
ensures that for each sensor_id, the average temperature is calculated over 5-minute event-time windows. To complete the logic, it is assumed that withWatermark("timestamp", "5 minutes") is used earlier in the pipeline to handle late events.
Explanation of why other options are incorrect:
Option A uses Window.partitionBy which applies to static DataFrames or batch queries and is not suitable for streaming aggregations.
Option B does not apply a time window, thus does not compute the rolling average over 5 minutes.
Option C incorrectly applies withWatermark() after an aggregation and does not include any time window, thus missing the time-based grouping required.
Therefore, Option D is the only one that meets all requirements for computing a time-windowed streaming aggregation.
NEW QUESTION # 67
How can a Spark developer ensure optimal resource utilization when running Spark jobs in Local Mode for testing?
Options:
- A. Configure the application to run in cluster mode instead of local mode.
- B. Increase the number of local threads based on the number of CPU cores.
- C. Use the spark.dynamicAllocation.enabled property to scale resources dynamically.
- D. Set the spark.executor.memory property to a large value.
Answer: B
Explanation:
When running in local mode (e.g., local[4]), the number inside the brackets defines how many threads Spark will use.
Using local[*] ensures Spark uses all available CPU cores for parallelism.
Example:
spark-submit --master local[*]
Dynamic allocation and executor memory apply to cluster-based deployments, not local mode.
NEW QUESTION # 68
A data engineer writes the following code to join two DataFrames df1 and df2:
df1 = spark.read.csv("sales_data.csv") # ~10 GB
df2 = spark.read.csv("product_data.csv") # ~8 MB
result = df1.join(df2, df1.product_id == df2.product_id)
Which join strategy will Spark use?
- A. Shuffle join, as the size difference between df1 and df2 is too large for a broadcast join to work efficiently
- B. Shuffle join, because AQE is not enabled, and Spark uses a static query plan
- C. Broadcast join, as df2 is smaller than the default broadcast threshold
- D. Shuffle join because no broadcast hints were provided
Answer: C
Explanation:
The default broadcast join threshold in Spark is:
spark.sql.autoBroadcastJoinThreshold = 10MB
Since df2 is only 8 MB (less than 10 MB), Spark will automatically apply a broadcast join without requiring explicit hints.
From the Spark documentation:
"If one side of the join is smaller than the broadcast threshold, Spark will automatically broadcast it to all executors." A is incorrect because Spark does support auto broadcast even with static plans.
B is correct: Spark will automatically broadcast df2.
C and D are incorrect because Spark's default logic handles this optimization.
Final answer: B
NEW QUESTION # 69
......
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